[LLM] ChatGPT Prompt Engineering for Developers - Summarizing
ยท
๐Ÿ› ๏ธ Tools/๐Ÿค– ChatGPT
https://www.deeplearning.ai/short-courses/chatgpt-prompt-engineering-for-developers/ ChatGPT Prompt Engineering for Developers What you’ll learn in this course In ChatGPT Prompt Engineering for Developers, you will learn how to use a large language model (LLM) to quickly build new and powerful applications. Using the OpenAI API, you’ll... www.deeplearning.ai 3 - Summarizing ์ •๋ฆฌ Setup import opena..
[LLM] ChatGPT Prompt Engineering for Developers - Iterative
ยท
๐Ÿ› ๏ธ Tools/๐Ÿค– ChatGPT
https://www.deeplearning.ai/short-courses/chatgpt-prompt-engineering-for-developers/ ChatGPT Prompt Engineering for Developers What you’ll learn in this course In ChatGPT Prompt Engineering for Developers, you will learn how to use a large language model (LLM) to quickly build new and powerful applications. Using the OpenAI API, you’ll... www.deeplearning.ai ChatGPT Prompt Engineering for Develo..
[LLM] ChatGPT Prompt Engineering for Developers - Guidelines
ยท
๐Ÿ› ๏ธ Tools/๐Ÿค– ChatGPT
https://www.deeplearning.ai/short-courses/chatgpt-prompt-engineering-for-developers/ ChatGPT Prompt Engineering for Developers What you’ll learn in this course In ChatGPT Prompt Engineering for Developers, you will learn how to use a large language model (LLM) to quickly build new and powerful applications. Using the OpenAI API, you’ll... www.deeplearning.ai ChatGPT Prompt Engineering for Develo..
[leetcode-48] Rotate Image
ยท
๐Ÿข One step
LeetCode-48 Rotate Image : You are given an n x n 2D matrix representing an image, rotate the image by 90 degrees (clockwise). note : You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.Answer :::python class Solution: def rotate(self, matrix: List[List[int]]) -> None: if len(matrix[0])==1: retu..
[leetcode-347] Top K Frequent Elements
ยท
๐Ÿข One step
LeetCode-347 Top K Frequent Elements : Given an integer array nums and an integer k, return the k most frequent elements. You may return the answer in any order. note : time complexity must be better than O(n log n), where n is the array s size.Over * :::python class Solution: def topKFrequent(self, nums: List[int], k: int) -> List[int]: if len(set(nums))==1: return [nums[0]] answer = [] count =..
[2023-3] ์Šต๊ด€์˜ ์•Œ๊ณ ๋ฆฌ์ฆ˜
ยท
๐Ÿ“š Book
์Šต๊ด€์˜ ์•Œ๊ณ ๋ฆฌ์ฆ˜ ์‹ ๊ฒฝ๋ง ๊ณผํ•™์ž๊ฐ€ ์ƒ๊ฐ ์Šต๊ด€์ด๋ž€? ์ฑ…์˜ ์ €์ž๋Š” ์Šคํƒ ํฌ๋“œ ๋Œ€ํ•™์˜ ๊ต์ˆ˜์ด๋‹ค. https://profiles.stanford.edu/russell-poldrack Russell Poldrack's Profile | Stanford Profiles Bio I grew up in a small town in Texas and attended Baylor University. After completing my PhD in experimental psychology at the University of Illinois in Urbana-Champaign, I spent four years as a postdoc at Stanford. I have held faculty positions at Mass..
๋‹คํ–ˆ๋‹ค
B's