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LeetCode-4

Median of Two Sorted Arrays : Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays.
note : The overall run time complexity should be O(log (m+n)).

Answer

        :::python

class Solution:    def findMedianSortedArrays(self, nums1: List[int], nums2: List[int]) -> float:        p = nums1 + nums2        p.sort()        if len(p)%2!=0:            median = p[len(p)//2]            else:            median = (p[len(p)//2]+p[len(p)//2-1])/2        return median

Result : 93ms Memory: 14mb

Median of Two Sorted Arrays

  • ๋‘ ๊ฐœ์˜ ์ •๋ ฌ๋œ ๋ฐฐ์—ด์ด ์ฃผ์–ด์งˆ ๋•Œ, ๋‘ ๋ฐฐ์—ด์˜ ์ค‘์•™๊ฐ’์„ ์ฐพ๋Š” ๋ฌธ์ œ์ž…๋‹ˆ๋‹ค.
  • ์˜ˆ๋ฅผ ๋“ค์–ด, ๋ฐฐ์—ด A = [1, 3, 5], ๋ฐฐ์—ด B = [2, 4, 6] ์ด ์ฃผ์–ด์ง€๋ฉด, ์ค‘์•™๊ฐ’์€ (3+4)/2 = 3.5 ๊ฐ€ ๋ฉ๋‹ˆ๋‹ค.
  • ๋‘ ๋ฐฐ์—ด์˜ ํฌ๊ธฐ๋Š” ๊ฐ™์€ ๊ฒฝ์šฐ๋„ ์žˆ์ง€๋งŒ, ๋‹ค๋ฅธ ๊ฒฝ์šฐ๋„ ์žˆ์œผ๋ฏ€๋กœ ์ฝ”๋“œ๋กœ ๊ตฌํ˜„ํ•  ๋•Œ์—๋Š” ์ด๋ฅผ ๊ณ ๋ คํ•˜์—ฌ ์ž‘์„ฑํ•ด์•ผ ํ•ฉ๋‹ˆ๋‹ค.
  • ์ด ๋ฌธ์ œ๋Š” ์ด์ง„ ๊ฒ€์ƒ‰์„ ํ™œ์šฉํ•˜์—ฌ ํ’€ ์ˆ˜ ์žˆ์Šต๋‹ˆ๋‹ค. ์ด์ง„ ๊ฒ€์ƒ‰์ด๋ž€ ๋ฐฐ์—ด์„ ๋ฐ˜์œผ๋กœ ๋‚˜๋ˆ„์–ด ํƒ์ƒ‰ํ•˜๋Š” ๋ฐฉ๋ฒ•์œผ๋กœ, ์‹œ๊ฐ„๋ณต์žก๋„๋Š” O(log(n+m)) ์ž…๋‹ˆ๋‹ค.
  • ์ด์ง„ ๊ฒ€์ƒ‰์„ ์ด์šฉํ•ด ๋‘ ๋ฐฐ์—ด์„ ๋‚˜๋ˆ„๊ณ , ๊ฐ๊ฐ์˜ ์ค‘๊ฐ„๊ฐ’์„ ๋น„๊ตํ•˜์—ฌ ์กฐ๊ฑด์— ๋”ฐ๋ผ ๋ฐฐ์—ด์˜ ์™ผ์ชฝ ๋˜๋Š” ์˜ค๋ฅธ์ชฝ ๋ถ€๋ถ„๋งŒ ํƒ์ƒ‰ํ•ฉ๋‹ˆ๋‹ค.
  • ๋งˆ์ง€๋ง‰์œผ๋กœ ์ค‘์•™๊ฐ’์„ ์ฐพ์•„ ๋ฐ˜ํ™˜ํ•ฉ๋‹ˆ๋‹ค.
๋ฐ˜์‘ํ˜•

'๐Ÿข One step' ์นดํ…Œ๊ณ ๋ฆฌ์˜ ๋‹ค๋ฅธ ๊ธ€

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